Please see an attachment for details Match the numbered statement below with its reason in a two-column proof. Use each reason only once. GivenJV = QG, OF = VG Prove OF = JQ G C. V 1 . JV = QG, OF VG A. Symmetric Property of Equality B. TransitiveProperty of Equality F. v 2 . JV = JQ + QV C. Given OG = QV+ VG D. Segment Addition Postulate Show more Show more Math GeometryGEOMETRY A 1A
